The \(m_l\) Quantum Number and Magnetic Fields. The orbital angular momentum of a p-electron is given as : Options (a) h/(√2π) (b) √3 x (h/2π) (c) √(3/2) x h/π (d) √6 x h/2π. New questions in Social Sciences. Correct Answer: h/(√2π) Explanation: Orbital Angular Momentum = h/(2π) x √(l(l+1)). A …
Strategy: Orbital angular momentum in related to azimuthal quantum number. Orbital angular momentum value of an electron for p orbital is 1 See answer ptparth2003 is waiting for your help. so => h/(2π) x √2 =? An electron possesses orbital angular momentum has a density distributions is no longer spherical. The magnetic quantum number, designated by the letter \(m_l\), is the third quantum numbers which describe the unique quantum state of an electron. For p orbital, l=1. directly to calculate the orbital angular momentum. Calculate the orbital angular momentum of an electron in a state of hydrogen. LifeissooBeautiful LifeissooBeautiful Explanation: The orbital angular momentum of a s electron is equal to 2 2πh. h/(√2π) Related Questions: PV/T= Constant. Add your answer and earn points. Use Eq.