2\displaystyle \int_{0}^2 \big\lceil 4-x^2 \big\rceil \, dx.2∫02⌈4−x2⌉dx. = ⌈x⌉⌈2x⌉=15. + These formulas show how adding integers to the arguments affect the functions: The above are never true if n is not an integer; however, for every x and y, the following inequalities hold: In fact, for integers n, both floor and ceiling functions are the identity: Negating the argument switches floor and ceiling and changes the sign: Negating the argument complements the fractional part: The floor, ceiling, and fractional part functions are idempotent: The result of nested floor or ceiling functions is the innermost function: due to the identity property for integers. {\displaystyle \operatorname {sgn}(x)\lfloor |x|\rfloor } 2 ( , and p {\displaystyle n} It takes single value whoes floor value is to be calculated. ⌋ As with floor functions, the best strategy with integrals or sums involving the ceiling function is to break up the interval of integration (or summation) into pieces on which the ceiling function is constant. In the second case, where r≥12, r \ge \frac12,r≥21, the equation becomes n(2n−1)=15, n(2n-1) = 15,n(2n−1)=15, so 2n2−n−15=0, 2n^2-n-15 = 0,2n2−n−15=0, or (n−3)(2n+5)=0. The exponent of the highest power of p that divides n! | {\displaystyle \lfloor \,\rfloor } Ceiling Function ceiling: R → Z. ceiling(x) = the smallest integer y such that y ≥ x. [ , and rounding towards even can be expressed with the more cumbersome [16], For positive integer n, and arbitrary real numbers m,x:[17]. ⌋ Similarly, the ceiling function maps x {\displaystyle x} to the least integer greater than or equal to x {\displaystyle x} , denoted ceil ( x ) {\displaystyle \operatorname {ceil} (x)} or ⌈ x ⌉ {\displaystyle \lceil x\rceil } . Notation: ⌊⋅⌋\lfloor \cdot \rfloor ⌊⋅⌋ denotes the floor function. − ⌋ ⌋ 16